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Mapel : Matematika
Materi : Lingkaran
Kelas : 8

1] Luas Lingkaran

= πr²
= 3,14 x 6²
= 3,14 x 36
= 113,04 cm²

2] Luas Lingkaran

= ¼ πd²
= ¼ x 3,14 x 15²
= ¼ x 3,14 x 225
= 176,625 cm²

3] Penyelesaian

= 100/360 x 6.300
= 10/36 x 6.300
= 5/18 x 6.300
= 1.750

4] Keliling Lingkaran

= 2πr
= 2 x 22/7 x 14
= 44 x 2
= 88 cm

5] Diameter Lingkaran

= K/π
= 22/22/7
= 22 x 7/22
= 7 cm

1)
[tex]l = \pi \times r {}^{2} [/tex]
L= 3,14 x 6 x 6
L=113,04

2) L= 3,14 x 15/2 x 15/2
L=176, 625

3) 100/360 x 6.300= 1750

4)
[tex]2\pi \times {r}[/tex]
2 x 22/7 x 14
88

5)22= 3,14 x d
22/3,14 =d
7= d

6)v = 1/3 x Lalas x t
= 1/3 x 45 x 20
= 300