Matematika

Pertanyaan

Hitunglah Sn dari deret-deret geometri berikut ini:
A. 1 + 4 + 16 + ... (n = 8)
B. 5 + 10 + 20 + ... (n = 6 )
C. 300 + (-150) + 75 + ... (n = 7)
D. 1/16 + 1/4 + 1 + ... ( n = 10 )

tolong jawab dengan benar

1 Jawaban

  • A)
    a = 1
    r = 4/1 = 4
    S8 = 1 x (4^8 - 1)/(4-1)
    = (65.536-1)/3
    = 65.535/3
    = 21.845

    B)
    a = 5
    r = 10/5 = 2
    S6 = 5 x (2^6 -1)/(2-1)
    = 5 x (64-1)/1
    = 5 x 63
    = 315

    C)
    a = 300
    r = -150/300 = -½
    S7 = 300 x ( 1 - ½^7)/(1-½)
    = 300 x (1 - 1/128)/½
    = 300x2x(128-1)/128
    = 600 x 127/128
    = 595,3125

    D)
    a = 1/16
    r = ¼/(1/16) = ¼ x 16/1 = 16/4 = 4
    S10 = 1/16 x ( 4^10 - 1)/(4-1)
    = 1/16 x (1.048.576 -1)/3
    = 1/16 x 1.048.575/3
    = 349.525/16
    = 21.845,3125

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