jika f(x)=(2x+5) (3x-3) nilai f(2)=

Kelas 8 Matematika
Bab Operasi Aljabar

f(x) = (2x + 5) . (3x - 3)
f(2) = (2 . 2 + 5) . (3 . 2 - 3)
f(2) = (4 + 5) . (6 - 3)
f(2) = 9 . 3
f(2) = 27

≡ penyelesaian :

f(x) = ( 2x + 5 ) ( 3x - 3 )

⇎maka, nilai f(2) :

f(2) = ( 2(2) + 5 ) ( 3(2) - 3 )
f(2) = ( 4 + 5 ) ( 6 - 3 )
f(2) = 9 × 3
f(2) = 27 [tex]~[/tex]