Di ketahui f(x)=4x(x^2 - 3x + 2).Maka nilai f'(2)adalh....

Semoga membantu yahh:)






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f(x) = 4x(x^2 - 3x + 2)

misalkan :
f(a) = 4x => f'(a) = 4
f(b) = x^2 - 3x + 2 => f'(b) = 2x - 3

maka :

f'(x) = f'(a) × f(b) + f(a) × f'(b)
f'(x) = 4(x^2 - 3x + 2) + 4x(2x - 3)
f'(x) = 4x^2 - 12x + 8 + 8x^2 - 12x
f'(x) = 12x^2 - 24x + 8

f'(2) = 12(2^2) - 24(2) + 8
f'(2) = 12(4) - 48 + 8
f'(2) = 48 - 48 + 8
f'(2) = 8

Jadi nilai f'(2) adalah 8