Matematika

Pertanyaan

(1-2^2/100)x(1-3^2/100)x1-4^2/100)x...x(1-99^2/100) adalah

1 Jawaban

  • Hati-hati, Bro.
    Ada ranjaunya.
    [tex]\displaystyle (1-\frac{2^2}{100})(1-\frac{3^2}{100})(1-\frac{4^2}{100})..(1-\frac{99^2}{100}) \\ \\ (1-\frac{2^2}{100})(1-\frac{3^2}{100})...(1-\frac{10^2}{100})...(1-\frac{99^2}{100}) \\ \\ (1-\frac{2^2}{100})(1-\frac{3^2}{100})...(\frac{100-100}{100})...(1-\frac{99^2}{100}) \\ \\ (1-\frac{2^2}{100})(1-\frac{3^2}{100})...\times 0\times ...(1-\frac {99^2}{100}) \\ $Apapun bilangan jika dikalikan 0 akan menghasilkan 0$ \\ $Hasil = $0[/tex]

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