jika 3log5=m dan 7log5=n. maka 35log15 =..

misal
3log5=m -> 5log3 = 1/m
7 lo5 = n -> 5log7 = 1/n
penyelesaian
35 log 15 = 5 log 35 / 5 log 15 = 5log7 + 5log5 / 5log5+ 5log3 = 1/m + 1 / 1/n +1 =1/m + 1 / 1/n +1 * n = n/m + n / n/n + n = n/m + n / n/n + n * m = m+mn / m+1
Jawabnaya adalah m ( 1+n)/m+1