suatu larutan natrium asetat,NaC2H3O2 mempunyai pH=10.Jika Ka asam asetat=10-5,maka kemolaran larutan tersebut adalah...

PH = 10
pOH = 14 - pH = 14 - 10 = 4
pOH = - log [OH-]
4 = - log [OH-]
[OH-] = 10⁻⁴

[OH-] = √Kw/Kb x M
10⁻⁴ = √10⁻¹⁴/10⁻⁵ x M
10⁻⁸ = 10⁻⁹ x M
M = 10 M
konsentrasi CH3COONa = 10 M