tentukan pH larutan H2SO4 pekat 98 persen sebanyak 1,8 mL; massa jenis 1,8 kg/L dilarutkan dalam 200mL air

volume zat h2so4=98%×1.8=1.764ml
masa h2so4=1.764×1.8=3.1752gram
mol h2so4=3.1752/98=0.0324mol=32.4mmol
molaritas h2so4=32.4/(200+1.8)=
32.4/201.8=0.16

[tex]ph = - log(h) \\ ph = - log(0.16 \times 2) \\ ph = - log(0.32 ) \\ ph = - log(3.2 \times 10 {}^{ - 1} ) \\ ph = 1 - log(3.2) [/tex]