Diketahui log 2 = a ; log 3 = b ditanya 27 log 32 + 3 log 64

log2 = a
log3 = b
27log32 + ³log64
= log32/log27 + log64/log3
= log2^5/log3³ + log2^6/log3
= 5a/3b + 6a/b
= (5a + 18a)/3b
= 23a/3b