diketahui 2log 3=x dan 3log 5 =y tentukan nilai dari 6 log120

6log 120 = 6log (20.6)
= 6log 20 + 6log 6
= (3log 20)/3log 6 + 1
= (3log (4.5))/(3log (3.2)) + 1
= (3log 4 + 3log 5)/(3log 3 + 3log 2) + 1
= (2. 3log 2 + 3log 5)/(1 + 1/(2log 3)) + 1
= (2/(2log 3) + 3log 5)/(1 + 1/(2log 3)) + 1
= (2/x + y)/(1 + 1/x) + 1
= (2 + xy)/(x + 1) + 1
= (2 + xy + x + 1)/(x + 1)
= (xy + x + 3)/(x + 1)