Diketahui segitiga ABC dengan sudut A=30 derajat, panjang sisi AC=8cm, dan BC=12cm. Nilai sudut tanB = ...

pakai aturan sinus
[tex] \frac{12}{ \sin(30) } = \frac{8}{ \sin(b) } [/tex]
[tex] \sin(b) = \frac{8 \times \sin(30) }{12} = \frac{8 \times \frac{1}{2} }{12} = \frac{4}{12} = \frac{1}{3} [/tex]
[tex] \tan(b) = \frac{1}{ \sqrt{ {3}^{2} } - {1}^{2} } = \frac{1}{ \sqrt{8} } = \frac{1}{2 \sqrt{2} } = \frac{ \sqrt{2} }{4} [/tex]