volume kerucut = 20cmpersegi jika d = 2x lebih besar t = 2x lebih besar volume baru?

Volume Baru

= [tex] \frac{ \frac{1}{3}\pi 2r^2 2t }{ \frac{1}{3}\pi r^2t } [/tex]

= [tex] \frac{2^2 \times 2}{1} [/tex]

= [tex] \frac{8}{1} [/tex] Volume Awal

= 8 × 20

= 160 cm³.