bangun di atas memiliki volume....cm3

Volume tabung=La×t
=phi×r×r×t
=22/7×7×7×12
=22×84
=1848
Volume kerucut=1/3×La×t
=1/3×22/7×7×7×6
=154×2
=308
Volumegabungan=volume tabung +Volume kerucut
=1848+308
=2156cm^3opsi B

Semoga bermanfaat

Jari-Jari (r) = 14 ÷ 2 = 7 cm
Tinggi Kerucut = 18 - 12 = 6 cm

[tex]\downarrow[/tex]

Volume Tabung
= π × r² × t
= [tex]\frac{22}{7}[/tex] × 7² × 12
= 1.848 cm³

Volume Kerucut
= [tex]\frac{1}{3}[/tex] × π × r² × t
= [tex]\frac{1}{3}[/tex] × [tex]\frac{22}{7}[/tex] × 7² × 6
= 308 cm³

[tex]\downarrow[/tex]

Volume Bangun
= 1.848 + 308
= 2.156 cm³

Jawaban: B