fungsi f(x)=x pangkat tiga dan g(x)=4x +2 nilai x jika f-1 o g-1 (x)=2 adallah

Diketahui :
f(x) = x^3
g(x)= 4x + 2
(f○g)^-1(x) = 2
Ditanyai :
x = ...?
Jawab:

f(x) = x^3
y = x^3
x = akar y
jadi f^-1(x) = akar x

g(x) = 4x + 2
y = 4x + 2
x = (y - 2)/4
jadi g(x) = (x - 2)/4

(f○g)^-1(x) = 2
(f^-1(g^-1(x))) = 2
f^-1((x - 2)/4) = 2
Akar((x -2)/4) = 2
(x - 2)/4 = 2^2
x - 2 = 4 × 4
x = 16 + 2 = 18

:-):-):-)