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Matematika
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Pertanyaan
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1 Jawaban
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1. Jawaban dhikboss
Persamaan matriks transformasi
[tex]\left[\begin{array}{ccc}x'\\y'\end{array}\right] = \left[\begin{array}{ccc}a&b\\c&d\end{array}\right] \left[\begin{array}{ccc}x\\y\end{array}\right][/tex]
Transformasi yang memetakan A(-2,1) ke A'(4,10)
[tex]\left[\begin{array}{ccc}4\\10\end{array}\right] =\left[\begin{array}{ccc}a&b\\c&d\end{array}\right] \left[\begin{array}{ccc}-2\\1\end{array}\right][/tex]
Sehingga diperoleh
-2a + b = 4 ....(1)
-2c + d = 10 ....(2)
Transformasi yang memetakan B(-1,2) ke B'(5,11)
[tex]\left[\begin{array}{ccc}5\\11\end{array}\right] =\left[\begin{array}{ccc}a&b\\c&d\end{array}\right] \left[\begin{array}{ccc}-1\\2\end{array}\right] [/tex]
Sehingga diperoleh
-a + 2b = 5 ....(3)
-c + 2d = 11 ....(4)
Dari persamaan (1) dan (3)
-2a + b = 4 | x2 | -4a + 2b = 8
-a + 2b = 5 | x1 | -a + 2b = 5
-------------------- -
-3a = 3
a = -1
b = 4 + 2a = 4 + 2(-1) = 4 - 2 = 2
Dari persamaan (2) dan (4)
-2c + d = 10 | x2 | -4c + 2d = 20
-c + 2d = 11 | x1 | -c + 2d = 11
-------------------- -
-3c = 9
c = -3
d = 10 + 2c = 10 + 2(-3) = 4
Pemetaan titik C(3,-2)
[tex] \left[\begin{array}{ccc}x'\\y'\end{array}\right] = \left[\begin{array}{ccc}-1&2\\-3&4\end{array}\right] \left[\begin{array}{ccc}3\\-2\end{array}\right] [/tex]
x' = -1(3) + 2(-2) = -7
y' = -3(3) + 4(-2) = -17
Jadi, bayangan titik C adalah C'(-7,-17)