(akar 6 -4) ^2 adalah

[tex] {( \sqrt{6 } - 4 })^{2} = { \sqrt{6} }^{2} - 2 \times \sqrt{6} \times 4 + {4}^{2} = 6 - 8 \sqrt{6} + 16 = 22 - 8 \sqrt{6} [/tex]

Mapel : Matematika
Materi : Aritmatika
Sub Materi : Penyederhanaan Akar
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[tex] (\sqrt{6} - 4) {}^{2} \\ = { \sqrt{6} }^{2} - {4}^{2} \\ = 6 - 16 \\ = - 10[/tex]
Semoga bermanfaat.....
-Prisco