jika a merupakan penyelesaian dar 2[3x -5]= -4[x -8] +8 niai dari k +10

[tex]2(3x - 5) = - 4(x - 8) + 8 \\ 6x - 10 = - 4x + 32 + 8 \\ 6x + 4x = 32 + 8 + 10 \\ 10x = 50 \\ x = 50 \div 10 \\ x = 5 \\ \\ k + 10 \\ 5 + 10 = 15[/tex]

2(3x - 5) = -4(x - 8) + 8
6x - 10 = -4x + 32 + 8
6x - 10 + 4x - 32 - 8 = 0
10x - 50 = 0
       10x = 50
           x = 50/10
           x = 5

   k = x
∴ k + 10 = 5 + 10
              = 15