jika f(x)=x pangkat 2 +3x-1 dan g(x)=x pangkat 2 -1,maka tentukan nilai (g o f)(x) dan (g o f)(0) adalah

f(x) = x² + 3x - 1
g(x) = x² - 1
(g o f)(x) = g(x² + 3x - 1)
             = (x² + 3x - 1)² - 1
             = x^4 + 6x³ + 7x² - 6x
(g o f)(0) = 0

f(x) = [tex]x^{2}[/tex] + 3x - 1
g(x) = [tex]x^{2}[/tex] - 1
(gof)(x) = [tex](x^{2} + 3x - 1)^{2}[/tex] - 1
(gof)(x) = ([tex]x^{4}[/tex] + [tex]3x^{3}[/tex] - [tex]x^{2}[/tex] + [tex]3x^{3}[/tex] + [tex]9x^{2}[/tex] - 3x - [tex]x^{2}[/tex] - 3x + 1) - 1
(gof)(x) = [tex]x^{4}[/tex] + [tex]6x^{3}[/tex] + [tex]7x^{2}[/tex] - 6x
(gof)(0) = [tex]0^{4}[/tex] + [tex]6(0)^{3}[/tex] + [tex]7(0)^{2}[/tex] - 6(0)
(gof)(0) = 0