Persamaan garis yank melalui titik (1,-2) dan sejajar denga garis 4x-y+3=0 adalah?

4x - y +3 =0
a = 4, b = -1
m1 = - a/b = - 4/-1 =4
sejajar m1 =m2
persamaan garis
y-y1 = m2 (x-x1)
y +2 =4 (x -1)
y=4x-4-2
y= 4x-6

4x-y+3=0

m= -a/b
= -4/-1
= 4

karena sejajar m nya sama
m= 4
x1,y1 = (1,-2)

y-y1 = m(x-x1)
y+2 = 4 ( x-1)
y+2 = 4x -4
4x - y - 6 = 0

semoga mmbantu