Mohon dibantu beserta cara selengkapnya

Orde A ==> data 1&2 ([B]&[C] konstan)
(0,01/0,03)^a = (1/8)/(1/8)
<=> (1/3)^a = 1 ; a = 0

Orde B ==> data 2&3 ([A] [C]
(0,02/0,04)^b = (1/8)/(1/4)
<=>(1/2)^b = (1/2) ; b =1

Orde C, pakai pasangan data bebas krn tidak ada data A dan B konstant.
Misalkan data 1 & 4.
(0,01/0,06)^0 (0,02/0,08)^2 (0,04/0,08)^c = (1/8)/1/2)
<=> 1 x (1/2)^2 x (1/2)^c = (1/8)/(1/2)
<=> 1/4 x (1/2)^c = 1/4 ; c = 0
Laju = k [a]^0 [b] [c]^0
k = laju/[b] = 0,06/(0,02)= 3