tolong dijawab yaa....skrng....

[tex]({ \sqrt{8} })^{2x - 6} = \frac{1}{6} \\ {( {2}^{ \frac{3}{2} } )}^{2x - 6} \\ ({ {2}^{3} })^{x - 3} \\ {2}^{3x - 9} \\ {2}^{3} \\ 8\\ \\ \\ \\ 3x - 9 = 0 \\ 3x = 9 \\ x = 9 \div 3 = 3[/tex]