diketahu: f(x) = x kuadrat -6x+5 dan g (x) = x-5, tentukan nilai (f/g)(1) ?

f(x) = x² - 6x + 5
      = (x - 1)(x - 5)
g(x) = x - 5

(f/g)(1) = ((x - 1)(x - 5)/(x - 5))(1)
          = (x - 1)(1)
          = 1 - 1
          = 0

(f/g)(x) = x^2-6x+5 / x -5
           = (x-5)(x-1) / x-5
           = x-1
(f/g)(1) = 1-1 = 0