Tolong bnatu darurat
Matematika
BILLA651
Pertanyaan
Tolong bnatu darurat
1 Jawaban
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1. Jawaban Sutr1sn0
11]
45° + 9a° = 180° (< lurus)
9a° = 180° - 45°
9a° = 135°
a = 135°/9°
a = 15°
45° = 15b° (< luar berseberangan)
b = 45°/15°
b = 3°
a + b
= 15° + 3°
= 18° (pilihan salah)
12]
< RPQ = < TQS (sehadap)
75° = 5Y°
Y = 75°/5°
Y = 15°
< PQR + < RQT + TQS = 180° (< lurus)
4Z° + 85° + 75° = 180°
4Z° + 160° = 180°
4Z° = 180° - 160°
4Z° = 20°
Z = 20°/4°
Z = 5°
< RPQ + < PQR + < PRQ = 180° (< segitiga)
75° + 20° + 5X° = 180°
95° + 5X° = 180°
5X° = 180° - 95°
5X° = 85°
X = 85°/5°
X = 17°
X + Y + Z
= 17° + 15° + 5°
= 37° (b)
13]
a = 50°
a° + b° = 180° (< lurus)
50° + b° = 180°
b = 180° - 50°
b = 130°
< d = < b (sehadap)
< d = 130°
b + d
= 130° + 130°
= 260° (d)