tolong jawab sama caranya. 2,3 dan 4

2. <ABC = 2a

2a + a = 180°
3a = 180°
a = 60°

<ABC = 2(60°) = 120°

3. <CBD = 110°

<ACB = <ABC

<ABC = 180° - 110° = 70°
<ACB = 70°

4. <CBD = 112°
<CAB = 42°

<ABC = 180° - 112° = 68°

<BCA = 180° - (42° + 68°)
<BCA = 180° - 110°
<BCA = 70°



semoga membantu