Sin 90 + cos 330 + sin 60 : tan 45 + tan 60

sin 90= 1
cos 330= 360-330
=30
cos 30= 1/2√3
sin60= 1/2√3
tan45= 1
tan60= √3



1+1/2√3+1/2√3:1+√3
penyelesaiannya kurang tau, cuma bisa bantu sampe situ, semoga membantu

[tex] \sin(90) + \cos(330) + \sin(60) \div \tan(45) + \tan(60) \\ = 1 + \frac{ \sqrt{3} }{2} + (\frac{ \sqrt{3} }{2} \div 1 )+ \sqrt{3} \\ = 1 + \frac{ \sqrt{3} }{2} + \frac{ \sqrt{3} }{2} + \sqrt{3} \\ = \frac{2 + \sqrt{3} + \sqrt{3} + 2 \sqrt{3} }{2} \\ = \frac{2 + 2 \sqrt{3} + 2 \sqrt{3} }{2} \\ = \frac{2( 1 + \sqrt{3} + \sqrt{3} )}{2} \\ = 1 + 2 \sqrt{3} [/tex]