diketahui f(x) = ( 2ax + (a - 1)x ) dx, f(1) = 3 dan f(2) = 0 . nilai a =

[tex]f(x)= \int\ {(2ax+(a-1)x)} \, dx = ax^2 + \frac{(a-1)}{2}x^2+C[/tex]
[tex]a + \frac{(a-1)}{2}+C =3[/tex]
[tex]4a + 2(a-1)+C =0[/tex]
[tex]3a + 2(a-1) -\frac{(a-1)}{2} = -3[/tex]
[tex]6a + 4(a-1) - (a-1) = -6[/tex]
[tex]6a + 4a - 4 - a + 1 = -6[/tex]
[tex]9a = -3[/tex]
[tex]a = -\frac{1}{3}[/tex]