jika kedalam 500gram air dilarutkan 3,42 gram senyawa nonelektrolit (mr=342) jika diketahui kb= 0,52 derajat celcius/m maka titik didik senyawa tsb

delta Tb = m x kb
delta Tb = massa/mr x 1000/massa air x kb
delta Tb = 3.42/342 x 1000/500 x 0.52
delta Tb = 0.0104
Tb = 100 + 0.0104 = 100.0104 derat celcius