tentuka konsentrasi ca(OH)2. dan Ph larutan

massa Ca(OH)2 = 0,37mg = 0,00037gram

mol Ca(OH)2 = 0,00037gr / 74gr.mol^-1
mol Ca(OH)2 = 0,000005mol

A. penentuan konsentrasi

volume = 100mL = 0,1L

M Ca(OH)2 = n/V
M Ca(OH)2 = 5x10^-6mol / 0,1L
M Ca(OH)2 = 5x10^-5M

B. penentuan pH larutan

Ca(OH2) > Ca^2+ + 2OH^-

[OH^-] = 2 x 5x10^-5
[OH^-] = 10^-4M

pOH = -log(10^-4)
pOH = 4

pH = 14 - 4
pH = 10