hasil integral (x^2+3x-4)dx

Integral X^2 +
= 1/3X^3 +3/2X^2-4X

x²+3x-4=0
(x+4)(x-1)
x=-4 dan x=1
=x²+3x-4
=⅓x³+3/2x²-4x <-- integral nya ..
=(⅓(1)³+3/2(1)²-4(1))-(⅓(-4)³+3/2(-4)²-4(-4))
=(⅓+3/2-4)-(64/3+24+24)
=(2+9-24/6)-(64+72+72/3)
=-13/6 - 208/3
=-13-416/6
=-429/6
=-143/3

Semoga bermanfaat .. Itu kalo saya gak salah hitung, kalo salah hapus saja ..