maka nilai a+b adalah

[tex] \frac{2(3 \sqrt{3} - \sqrt{2})}{ \sqrt{3} + \sqrt{2}} = a + b \sqrt{6} \\ 2 \times \frac{3 \sqrt{3} - \sqrt{2} }{ \sqrt{3} +\sqrt{2} } \times \frac{ \sqrt{3} - \sqrt{2} }{ \sqrt{3} - \sqrt{2} } = 2 \times \frac{9 -4\sqrt{6} +2 }{3 - 2} = \\ 2 \times (11-4\sqrt{6} ) = 22 - 8\sqrt{6} = a + b \sqrt{6} \\ a = 22 \\ b = -8\\ a + b = 14[/tex]