1-sinx/cos2x=1/1+sin x

[tex] \frac{1 - \sin(x) }{ \cos(2x) } = \frac{1}{1 + \sin(x) } \\ \cos(2x) = (1 - \sin(x) )(1 + \sin(x) ) \\ { \cos(x) }^{2} - { \sin( x ) }^{2} = 1 - { \sin(x) }^{2} \\ { \cos(x) }^{2} + { \sin(x) }^{2} - { \sin(x) }^{2} = 1 \\ \cos(x) = 1 \\ untuk \: 0 \leqslant x \leqslant 360 \\ x = 0 \: atau \: x = 360 \\ [/tex]
Himpunan penyelesaian :
{0,360}