Selesaikan 1. |3x - 2| ≥ -3 2. |-2x + 4| = 6 3. [tex] \frac{2x-3}{5} - \frac{5x+1}{2} [/tex] jawab beserta caranya. Terima kasih

1. 3X-2 [tex] \geq [/tex]-3
     3X[tex] \geq [/tex]-3+2
 =3X[tex] \geq -1[/tex]
X = 3/-1
X= -3
2. -2X+4 = 6
-2X = 6-4
-2X = 2
X=-1
3. [tex]\frac{2x-3}{5} - \frac{5x+1}{2} 2x(2)-3(2)=-5x(5)+1(5) 4x-6=-25x+5 4x +25x =5-6 29x=-1 x=-29[/tex]

1. (3x-2)^2 ≥ -3^2
9x^2 - 12x + 4 ≥9
9x^2 - 12x - 5 ≥ 0
(3x + 1) (3x - 5) ≥ 0
x ≤ - 1/3  atau x ≥ 5/3

2. (-2x + 4)^2 = 6^2
4x^2 - 16 x + 16 = 36
4x^2 - 16x - 20 = 0
x^2 - 4x - 5 = 0
(x - 5)(x+1)
x = 5 atau x = -1