fungsi f dinyatakan dengan rumus f(x)=ax + b. jika f(2)=3 dan f(-3)= 13, nilai dari f(0) adalah

f(x) = ax + b

f(2) = a(2) + b = 3
= 2a + b = 3

f(-3) = a(-3) + b = 13
-3a + b = 13

eliminasi b
2a + b = 3
-3a + b = 13
__________-
5a = -10
a = -2

mencari a
2(-2) + b = 3
-4 + b = 3
b = 3 + 4
b = 7

f(0) = 2(0)+7
= 0 + 7
= 7

f(x) = ax + b

f(2) = a(2) + b = 3
f(-3) = a(-3) + b = 13

2a + b = 3
-3a + b = 13

5a = -10
a = -2

f(2) = ax + b = 3
-2(2) + b = 3
-4 + b = 3
b = 3+4
b = 7

f(0) = -2(0) + 7
= 0 + 7
= 7