Sebanyak 10 ml larutan CH3COONa memiliki ph 8 jika diketahui ka 10-5 tentukan massa garam CH3COONa yg terlarut dalam 200 ml larutan?(diketahui Ar:H=1 g/mol ,C=

CH3COONa garam bersifat basa
pOH=14-8=6
[OH-]= 10-6
[tex][OH {}^{ - } ] = \sqrt{ \frac{kw}{ka} \times M} \\ {10}^{ - 6} \: = \sqrt{ \frac{ {10}^{ - 14} }{ {10}^{ - 5} } \times M} \\ {10}^{ - 12} = {10}^{ - 9} \times \: M \\M = {10}^{ - 3} [/tex]
[tex]M = \frac{m \times 1000}{mr \times v} \\ {10}^{ - 3} = \frac{m \times 1000}{82 \times 0.2} \\ M= 16.4 \: gram \: [/tex]