diketahui P sudut lancip. jika tan P =5√11 per 11.nilai sin P =

[tex] \sin(p) = \frac{5}{ \sqrt{ { \sqrt{11} }^{2} + {5}^{2} } } = \frac{5}{ \sqrt{11 + 25} } = \frac{5}{ \sqrt{36} } = \frac{5}{6} [/tex]